Library pigeonhole_principle.pigeonhole_principle

This module presents a proof of the pigeon hole principle, which states that if you place n things into m containers, and n > m, then one or more of the containers have more than one thing in it.
Our proof proceeds by contradiction. We first show that if we have a collection of containers, cs, where every container is either empty or has a single item in it, then the number of items contained in all of the containers is less than or equal to the number of containers.
Then we show that if, the number of items contained within a collection of containers is greater than the number of containers, and every container is either empty or has a single item in it, we have a contradiction. Accordingly, we cannot place n items into m collections without placing more than one item in a single container.
Copyright (C) 2018 Larry D. Lee Jr. <llee454@gmail.com>
This program is free software: you can redistribute it and/or modify it under the terms of the GNU Lesser General Public License as published by the Free Software Foundation, either version 3 of the License, or (at your option) any later version.
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Require Import base.
Require Import List.
Require Import Lt. Require Import Compare_dec. Require Import PeanoNat.
Module Pigeonhole_Principle.

I. Basic Concepts

Represents things (such as pigeons).
Parameter thing : Set.

Represents containers (such as cubbies).
Definition container := list thing.

Represents some collection of containers.
Definition containers := list container.

Counts the number of things in a container.
Definition container_num_things := length (A := thing).

Counts the number of containers.
Definition num_containers := length (A := container).

Counts the number of things in some containers.
Definition num_things (cs : containers) : nat
  := fold_right (fun c n => container_num_things c + n) 0 cs.

Accepts a container and asserts that it is either empty or has only one item in it.
Definition container_ok (c : container) : Prop
  := container_num_things c <= 1.

This lemma proves that the OK predicate is decideable.
Note: we will need this when proving that ~ Forall container_ok implies Exists ~ container_ok.
Definition container_ok_dec
  : forall (c : container), {container_ok c}+{~ container_ok c}
  := fun c => le_dec (container_num_things c) 1.

Accepts a set of containers and asserts that all of the containers are either empty or only contain a single item.
Definition containers_ok (cs : containers) : Prop
  := Forall container_ok cs.

II. Fundamental Proof

This theorem proves that given a collection of containers, where every container is either empty or has one item in it, then the number of items contained in all of the containers must be less than or equal to the number of containers.
Theorem num_things_num_containers
  : forall cs : containers,
     containers_ok cs ->
     num_things cs <= num_containers cs.
Proof
  let T cs := containers_ok cs -> num_things cs <= num_containers cs in
  list_ind T
    
    (fun _ => le_0_n 0)
    
    (list_ind
      (fun xs => forall cs, T cs -> T (xs :: cs))
      
      (fun cs
        (H : T cs)
        (H0 : containers_ok (nil :: cs))
        => let H1
             : num_things cs <= num_containers cs
             := H (Forall_tail nil cs H0) in
           (le_S
             (0 + num_things cs)
             (num_containers cs)
             (H1 || a <= num_containers cs @a by plus_O_n (num_things cs))))
      
      (fun x0
        => list_ind
             (fun xs => _ -> forall cs, T cs -> T ((x0 :: xs) :: cs))
             
             (fun _ cs
               (H : T cs)
               (H0 : containers_ok ((x0 :: nil) :: cs))
               => let H1
                    : num_things cs <= num_containers cs
                    := H (Forall_tail (x0 :: nil) cs H0) in
                  le_n_S (num_things cs) (num_containers cs) H1
                  || a <= S (num_containers cs) @a by Nat.add_1_l (num_things cs))
             
             (fun x1 xs _ _ cs
               (H : T cs)
               (H0 : containers_ok ((x0 :: x1 :: xs) :: cs))
               => False_ind
                    (num_things ((x0 :: x1 :: xs) :: cs) <= num_containers ((x0 :: x1 :: xs) :: cs))
                    ((Nat.nle_succ_0 (length xs))
                      (le_S_n (S (length xs)) 0 ((Forall_inv H0) : S (S (length xs)) <= 1)))))).

III. The Pigeonhole Principle

This lemma proves that if we have a collection of containers and the number of things in the containers is greater than the number of the containers then not all of the containers can be empty or have only one thing in it.
Lemma lemma_0
  : forall cs : containers,
    num_things cs > num_containers cs ->
    ~ containers_ok cs.
Proof fun cs
       (H : num_containers cs < num_things cs)
       (H0 : containers_ok cs)
       => le_not_lt
            (num_things cs)
            (num_containers cs)
            (num_things_num_containers cs H0)
            H.

This lemma proves that if we have a collection of containers and the number of things in the containers is greater than the number of containers, then one of the containers cannot be empty or have only one item in it.
Lemma lemma_1
  : forall cs : containers,
     num_things cs > num_containers cs ->
     Exists (fun c : container => ~ container_ok c) cs.
Proof fun cs H
       => neg_Forall_Exists_neg container_ok_dec (lemma_0 cs H).

This theorem proves that if we are given a collection of containers and the number of things in those containers is greater than the number of containers, then one or more of the containers has more than one thing in it.
Theorem pigeonhole_principle
  : forall cs : containers,
     num_things cs > num_containers cs ->
     Exists (fun c : container => container_num_things c > 1) cs.
Proof fun cs H
       => Exists_impl
            (fun c (H0 : ~ container_ok c)
              => not_le (container_num_things c) 1 H0)
            cs
            (lemma_1 cs H).

End Pigeonhole_Principle.